2x-4*4x=4x^2

Solution for 2x-4*4x=4x^2 equation:

2x-4*4x=4x^2

We move all terms to the left:

2x-4*4x-(4x^2)=0

determiningTheFunctionDomain
-4x^2+2x-4*4x=0

Wy multiply elements

-4x^2+2x-16x=0

We add all the numbers together, and all the variables

-4x^2-14x=0

a = -4; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-4)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-4}=\frac{0}{-8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-4}=\frac{28}{-8}
=-3+1/2
$